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x^2+2x+1=3x-31
We move all terms to the left:
x^2+2x+1-(3x-31)=0
We get rid of parentheses
x^2+2x-3x+31+1=0
We add all the numbers together, and all the variables
x^2-1x+32=0
a = 1; b = -1; c = +32;
Δ = b2-4ac
Δ = -12-4·1·32
Δ = -127
Delta is less than zero, so there is no solution for the equation
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